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designed by Kayo Arimoto
Now at Electronic and Computer Engineering , Musashi Institute of Technology,
All e-mail should be addressed to:
arimoto@iname.com
Postal mail should be addressed to:
Akio Arimoto
Department of Electronics and Computer Engineering
Musashi Institute of Technology
|
math.LA/0204276
A Simple Proof of the Classification of reference Ito http://www.math.cs.musashi-tech.ac.jp/~arimoto/mathematics/ito/ITO1996.PDF Farenick http://www.math.cs.musashi-tech.ac.jp/~arimoto/mathematics/farenick.pdf |
l
Completeness
of Trigonometric System with Integer Indices
, psfile
Journal of Approximation Theory, vol.112,no.2,
Zbl 0988.42007
Arimoto,
Akio
Completeness of trigonometric system with integer indices $\{ e^{inx};x\in\Re\}$. (English)
[J] J.
Approximation Theory 112, No.2, 311-317 (2001). [ISSN 0021-9045]
Summary: Necessary and sufficient conditions are given which ensure the completeness
of the trigonometric systems with integer indices; $\{e^{inx}; x\in{\germ
R}\}^\infty_{n= -\infty}$ or $\{e^{inx}; x\in{\germ R}\}^\infty_{n=1}$ in
$L^\alpha(\mu,{\germ R})$, $\alpha\ge 1$. If there exists a support $\Lambda$
of the measure $\mu$ which is a wandering set, that is, $\Lambda+ 2k\pi$, $k=
0,\pm 1,\pm 2,\dots$, are mutually disjoint for different $k$'s, then the
linear span of our trigonometric system $\{e^{inx}; x\in{\germ
R}\}^\infty_{n=-\infty}$ is dense in $L^\alpha(\mu,{\germ R})$, $\alpha\ge 1$.
The converse statement is also true.
MSC 2000:
*42A65 Completeness of sets of functions
MATH
Database 1931-1998
a service of the European Mathematical Society
http://www.emis.de/cgi-bin/MATH
in MATH Database, Zentralblatt fur Mathematik /
Mathematics Abstracts:
Copyright (c) 1997,1998 European
Mathematical Society, FIZ Karlsruhe & Springer-Verlag.
[ZB/w3] Retrieval Software :
Copyright (c) 1996 Cellule MathDoc, UJF & CNRS.
-----------------------------------------------------------------------
870.44004
Arimoto,
Akio; Ito, Takashi
Singularly positive definite sequences and
parametrization of extreme points. (English)
[J]
Linear Algebra Appl. 239, 127-149 (1996). [ISSN 0024-3795 ]
Authors'
abstract: In the truncated classical moment problems, the set of all solutions
constitutes a convex set of positive measures. We are concerned with extreme
points of this convex set. It is shown that the extreme points can be
characterized in terms of the singularly positive definite extensions of a
given positive definite finite sequence.
[ P.Ressel
(Eichstaett) ]
Keywords:
truncated moment problem; positive definite sequence; singularly positive
definite extension; extreme points; convex set
Classification:
*44A60
Moment problems
46A55
Convexity in topological linear spaces
-----------------------------------------------------------------------
641.60049
Arimoto,
Akio
Approximation of the finite prediction for a weakly
stationary process. (English)
[J]
Ann. Probab. 16, No.1, 355-360 (1988). [ISSN
0091-1798]
Some estimation
problems for the difference between the finite predictor and infinite predictor
of stationary stochastic processes are obtained. These estimates have a more
precise order than the previous one obtained by the author [Ann. Inst. Stat.
Math. 33, 101-113 (1981; Zbl. 484.60031)].
[ M.P.Mokljacuk ]
Citations:
Zbl.484.60031
Keywords:
prediction; estimation problems
Classification:
*60G25
Prediction theory
60K20
Appl. of Markov renewal processes
60G10
Stationary processes
-----------------------------------------------------------------------
484.60031
Arimoto,
Akio
Asymptotic behavior of difference between a finite
predictor and an infinite predictor for a weakly stationary stochastic process. (English)
[J]
Ann. Inst. Stat. Math. 33, 101-113 (1981). [ISSN
0020-3157]
Keywords:
weakly stationary; prediction error
Classification:
*60G25
Prediction theory
62M20
Prediction, etc. (statistics)
60G10
Stationary processes
60G15 Gaussian processes
482.60035
Arimoto,
Akio
On the order of complete regularity for a weakly
stationary random sequence. (English)
[J]
Citations:
Zbl.203.502
Keywords:
stationary random sequence; complete linear regularity; Hardy class; strong
mixing condition; time series; modulus of continuity
Classification:
*60G10
Stationary processes
60G17
Sample path properties
------------------------------------------------------------
351.60039
Arimoto,
Akio
Note
on the strong law of large numbers for a weakly stationary stochastic process. (English)
[J]
Rep. Stat. Appl. Res., Un. Jap.
Sci.
Classification:
*60G10
Stationary processes
60F15
Strong limit theorems
----------------------------------------------------------------------
321.60029
Arimoto,
Akio
On the asymptotic uncorrelatedness of Fourier
coefficients of a stationary stochastic process. (English)
[J]
Rep. Stat. Appl. Res., Un. Jap.
Sci.
Classification:
*60G10
Stationary processes
-----------------------------------------------------------------------
395.62031
Arimoto,
Akio
On
the estimation of the probability density of a distribution function. (English)
[J]
Keio Math. Semin. Rep. 1, 31-35
(1973). [ISSN 0388-3469]
Keywords:
ORDERS OF CONSISTENCY; KERNEL TYPE ESTIMATOR; ASYMPTOTIC UNBIASEDNESS;
NONPARAMETRIC ESTIMATION OF DENSITIES
------------------------------------------------------------
368.62083
Arimoto,
Akio
Some theorems for harmonizable stochastic processes. (English)
[CA] Stoch. Processes, Keio math. Semin. Rep. No.1, 24-30 (1973).
Classification:
*62G05
Nonparametric estimation
------------------------------------------------------
385.60040
Arimoto,
Akio
Some theorems for harmonizable stochastic processes. (English)
[J]
Keio Math. Semin. Rep. 1, 24-29
(1973). [ISSN 0388-3469]
Classification:
*60G12
General second order processes
----------------------------------------------------
251.60030
Arimoto,
Akio
On the degree of approximation of harmonizable
stochastic processes by the smoothing procedure. (English)
[J]
Rep. Stat. Appl. Res., Un. Jap.
Sci.
Classification:
*60G10
Stationary processes
60G35
Appl. of stochastic processes
We must read the
following papers to write more original papers.
Yoshino,Takashi 1999 The conditions that the product of Hankel
operators is also a Hankel Operator Arch.Math.73 146-153
Ikramov,Kh.D. 1994 Describing Normal Toeplitz Matrices
Comp.Maths
Math.Phys. 34,3,399-404
Gel'fgat,V.I. 1995 A Normality Criterion for Toeplitz
matrices
Comp.Maths
Math.Phys. 35,9,1147-1150
Ikramov,Kh.D.;Chugunov,V.N. 1996 Normality Condition for a Complex Toeplitz
Matrix
Comp.Maths
Math.Phys. 36,2,131-137
Gel'fgat,V.I. 1998 Commutation
Criterion for Toeplitz Matrices
Comp.Maths
Math.Phys. 38,1,7-10
Preprints, Preprints from
internet 
Jussi
Vaisala, A survey of near isometries
11/Jan/2002
http://www.helsinki.fi/~jvaisala/preprints.html
General
Solution for a linear Prediction Problem of Stationar Processes ( V.M.Adamian,
D.Z.Arov) pdf
Condition
that Toeplitz operator is normal in the Bergman space.( not yet completed)
Algebra
of Quantum Mechanics (pdf)
Banach
space problem solved by W.T.Gowers Fields Medalist 1998
Shuichi,Maeda
A.E.,Nussbaum
L.D.Pitt
Sodin,Misha
Printed Journals containing Mathematics and with Internet
sites
History of
Mathematics and more
Featured Review
(American Mathematical Society)
References for Moment Problem (2001.11.7)
A characterization
of N-extremal measures for the Hamburger moment problem,(in
preparation)
Hamburger Moment Problem references are Here
On Canonical Solutions to the Hamburger Moment Problem, Hokkaido
University Technical Report Series in Mathematics,Ser#.41,pp.71-75(1996)
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Yes, I will appreciate your offered hand (collaboration,jobs,marriage,or any other opportunities).

We should recognize an importance of "internet" for our research work.I give here an example for my case.
Hamburger moment problem
If you are interested in the following articles, don't hesitate to contact mevia e-mail or other means.
Let (1) { s_0,s_1,...} be a given positive definite Hamburger moment sequence, in other words for some positive measure \mu we can represent moments as s_k=\int{x^k d\mu}. In case when representing measure \mu is unique, we say (1) is determinate. Otherwise we say (1) is indeterminate. Now by a first backward extension of (1), we mean a positive definiteHamburger moment sequence
(2) { t_0,t_1,t_2(=s_0),t_3(=s_1),...}.
And by a second backward extension of (1), we mean a first backward extension of (2), etc. F.M.Wright[1956 Proc.of AMS,413-422] proved Theorem: (a)An indeterminate Hamburger moment sequence can be always backward extendable once. (b)(1) is an indeterminate Hamburger sequence and if (2) is a first backward extension of (1), then (2) is an indeterminate Hamburger moment sequence if and only if (t_0,t_1) is an interior of some closed parabolic region. We can easily see that if we take ( t_0,t_1) on the boundary of this parabolic region, (2) becomes a determinate moment sequence. Our conjecture is that " N-extremal measures are always found in such way." Here we mean by N-extremal measure \mu such that polynomials are dense in L^2(\mu).[N.I.Akiezer, The classical moment problem,Oliver and Boyd, Edinburgh 1965, p.43] Any commens will be appreciated.1.2It is very happy that I can announce here many correspondences to this news.
From hrubin@stat.purdue.edu Wed Dec 28 05:49:31 1994Subject: Re: Hamburger moment problemNewsgroups: sci.math.researchOrganization: Purdue University Statistics DepartmentStatus: ROIn article <9412250520.AA26763@tansei2.tansei.cc.u-tokyo.ac.jp> you write:>> Let>(1) { s_0,s_1Your result MUST be SLIGHTLY wrong. I read Shohat and Tamarkinmany years ago.An extremal solution of an indeterminate moment problem is givenby putting maximal mass at a point; in fact, at all points whereit puts mass. The resulting measure is discrete. So if 0 is notin the spectrum of the distribution, there must exist moments oforder -1 and -2. If the new problem (the backwards extension) isnot determined, we would have a contradiction to the density ofthe polynomials for the original problem in L_2; the nasc for amoment problem to have a unique solution is that either the first forward extension has a unique solution OR 1 is in theL_2 closure of the polynomials divisible by x.The case where 0 is a point of the spectrum, however, is notof this type, although it is a limit.So the final answer is that N-extremal measures are eitherfound in this way, or are the limits of such at t_0 -> \infty.-- Herman Rubin, Dept. of Statistics, Purdue Univ., West Lafayette IN47907-1399Phone: (317)494-6054hrubin@stat.purdue.edu (Internet, bitnet) {purdue,pur-ee}!a.stat!hrubin(UUCP)Message 2:From nevai@ops.mps.ohio-state.edu Thu Jan 5 05:25:40 1995Message-Id: <9501042024.AA16992@ops.mps.ohio-state.edu>Subject: Hamburger moment problem...To: a80919@tansei.cc.u-tokyo.ac.jpDate: Wed, 4 Jan 1995 15:24:28 -0500 (EST)Cc: askey@math.wisc.edu (Dick Askey)Reply-To: nevai@math.ohio-state.edu (Paul Nevai)Organization: The Ohio State UniversityX-Mailer: ELM [version 2.4 PL23]Content-Type: textStatus: ROOur conjecture is that " N-extremal measures are always found in such way."Here we mean by N-extremal measure \mu such that polynomials are dense inL^2(\mu).[N.I.Akiezer, The classical moment problem,Oliver and Boyd,Edinburgh 1965, p.43]Dear Professor Akio (is this your family name?):Can you be more specific about what you mean by "in such way"? Happy new year...Paul N.Paul Nevai pali+@osu.eduDepartment of Mathematics nevai@math.ohio-state.eduThe Ohio State University nevai@ohstpy.bitnet231 West Eighteenth Avenue 1-614-292-3317 (Office)Columbus, Ohio 43210-1174 1-614-292-5310 (Answering Machine)The United States of America 1-614-292-1479 (Math Dept Fax)1.3.I sent a mail to Prof. Nevai at 1/6/95.Dear Professor Nevai:Thank you for your correspondence. My family name is Arimoto. In Japanese styleI am called Arimoto Akio.If we have an indeterminate Hamburger moment sequence(1) { s_0,s_1,s_2,...},then for any real y \sum_{p=0}^{\infty}[X_p(0)+yY_p(0)]^2 is finite. ( Here Y_p are orthonormal polynomials and X_p are polynomials of second kind,i.e. Akiezer's P_k and Q_k.).Let (2) x = \sum_{p=0}^{\infty}[X_p(0)+yY_p(0)]^2.By virtue of Wright's theory we have a determinate moment sequence(3) {x,y,s_0,s_1,s_2,...},which is a first backward extension of (1). I guess (3) determines all the N extremal measures "in such way" where(x,y)'s are taken from the points on the parabola (2).The other day,Herman Rubin, Dept. of Statistics, Purdue Univ.,mailed me>Your result MUST be SLIGHTLY wrong. I read Shohat and Tamarkin>many years ago.>An extremal solution of an indeterminate moment problem is given>by putting maximal mass at a point; in fact, at all points where>it puts mass. The resulting measure is discrete. So if 0 is not>in the spectrum of the distribution, there must exist moments of>order -1 and -2. If the new problem (the backwards extension) is>not determined, we would have a contradiction to the density of>the polynomials for the original problem in L_2; the nasc for a>moment problem to have a unique solution is that either the >first forward extension has a unique solution OR 1 is in the>L_2 closure of the polynomials divisible by x.>The case where 0 is a point of the spectrum, however, is not>of this type, although it is a limit.>So the final answer is that N-extremal measures are either>found in this way, or are the limits of such at t_0 -> \infty.Despite of his advice, I believe these troubles will be conqured.oooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo akio arimoto department of industrial engineering|o email:a80919@tansei.cc.u-tokyo.ac.jp musashi institute of technology |o telephone:(03) 3703-3111 setagaya-ku tamazutsumi 1-28-1 | o telefax: (03) 5707-2136 tokyo 158, japan |ooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo1.4I posted the second news at 1/10/95.Dear Modelator Let \mu be a positive Borel measure on R and its Stieltjes transform I_{\mu}(z)=\int{d\mu(t)/(z-t)}, which is a holomorphic function of z in C-R.A Hamburger's moment sequence is given by s_k=\int{x^k d\mu(x)},k=0,1,2,3,... Let P_k(z) be orthonormal polynomials in L^2(\mu) and their associated secondpolynomials: Q_k(z)=\int{(P_k(z)-P_k(t))/(z-t)}d\mu(t).
The Fourier coefficient of 1/(z-t) with respect to P_k(t) is easily seento be I_{\mu}(z)P_k(z)-Q_k(z). The density of polynomials in L^2(\mu) isequivalent to that 1/(z-t) is precisely approximated by polynomials in L^2(\mu). These are the contents of the following statement. Proposition: \mu is N-extremal iff the Parseval equality holds:(1) \sum_{k=0}^{\infty}|I_{\mu}(z)P_k(z)-Q_k(z)|^2 =\int{d\mu(t)/(|z-t|^2)}. For z=0, (1) becomes the Wright's parabola stated in my previous article <9412250520.AA26763@tansei2.tansei.cc.u-tokyo.ac.jp> : (2) \sum_{k=0}^{\infty}(s_1P_k(0)+Q_k(0))^2 =s_2,where s_1,s_2 are given by the first backward extension of {s_0,s_1,...}.Our conjecture was the converse of the above deduction,i.e. (2)==>(1).It is pointed out by H.Rubin that the case where 0 is a support point of \mucauses us some troubles. Can we now prove or disprove our conjecture? Acknowledgements for replies from: Herman Rubin and Paul Nevai. Thanks for more helps in advance.ooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo akio arimoto department of industrial engineering oo email:a80919@tansei.cc.u-tokyo.ac.jp musashi institute of technology oo telephone:(03) 3703-3111 setagaya-ku tamazutsumi 1-28-1 o o telefax: (03) 5707-2136 tokyo 158, japan oooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooI have again many correspondences.From jroach@Starbase.NeoSoft.COM Thu Jan 12 02:52:51 1995Date: Wed, 11 Jan 1995 11:52:48 -0600From: Jack Roach Message-Id: <199501111752.LAA00604@Starbase.NeoSoft.COM>X-Provider: NeoSoft, Inc.: Internet Service Provider (713) 684-5969To: a80919@tansei.cc.u-tokyo.ac.jp (A80919)Subject: Re: Hamburger moment problem (2)Newsgroups: sci.math.researchX-Newsreader: TIN [version 1.2 PL2]Status: ROYou are probabily aware of the connection with continued fractions but if not, you may want to see H. S. Wall, "The Analytic Theory of Continued Fractions," Van Nostrand (1948), reprinted by Chelsea (1967), LC # 66-24296. There is quite a bit on various moment problems in this book.Jack Roach --------------------------------------------------------------------------From berg@math.ku.dk Wed Jan 18 21:52:21 1995Received: by gelfand id AA05455Date: Wed, 18 Jan 1995 13:51:42 +0100From: Christian Berg Message-Id: <199501181251.AA05455@gelfand>To: Walter=Van=Assche%twi%WIS@cc3.kuleuven.ac.beSubject: Hamburger moment problem...Cc: nevai@math.ohio-state.edu, a80919@tansei.cc.u-tokyo.ac.jpX-Char-Esc: 29Status: RODear Akio Arimoto, Walter Van Assche, Paul Nevai,Via Paul and Walter I received the following: Forwarded to: email@pub@wis[berg@math.ku.dk] cc: Comments by: Walter Van Assche@twi@WIS Comments: This is certainly of interest to you, Christian. The best for 1995! Walter Van Assche -------------------------- [Original Message] ------------------------- This is interesting! Take care...Paul ############################################################################# >From a80919@tansei.cc.u-tokyo.ac.jp Tue Dec 27 15:57:40 EST 1994 Newsgroups: sci.math.research Subject: Hamburger moment problem Date: Sun, 25 Dec 94 14:20:40 JST Let (1) { s_0,s_1,...} be a given positive definite Hamburger moment sequence, in other words for some positive measure \mu we can represent moments as s_k=\int{x^k d\mu}. In case when representing measure \mu is unique, we say (1) is determinate. Otherwise we say (1) is indeterminate. Now by a first backward extension of (1), we mean a positive definiteHamburger moment sequence
(2) { t_0,t_1,t_2(=s_0),t_3(=s_1),...}.
And by a second backward extension of (1), we mean a first backward extension of (2), etc. F.M.Wright[1956 Proc.of AMS,413-422] proved Theorem: (a)An indeterminate Hamburger moment sequence can be always backward extendable once. (b)(1) is an indeterminate Hamburger sequence and if (2) is a first backward extension of (1), then (2) is an indeterminate Hamburger moment sequence if and only if (t_0,t_1) is an interior of some closed parabolic region. We can easily see that if we take ( t_0,t_1) on the boundary of this parabolic region, (2) becomes a determinate moment sequence. Our conjecture is that " N-extremal measures are always found in such way." Here we mean by N-extremal measure \mu such that polynomials are dense in L^2(\mu).[N.I.Akiezer, The classical moment problem,Oliver and Boyd, Edinburgh 1965, p.43] Any commens will be appreciated.Here are the comments of Christian Berg:Let $\mu$ be an indeterminate probability. I write $\mu\sim\nu$ todenote that the measure $\nu$ has the same moments as $\mu$ and I put$V_\mu=\{\nu\mid \mu\sim\nu\}.$ For the parabolic region $P\mu$ associated to$\mu$ it is convenient to consider the set of measures $M_\mu=\{\sigma\mid t^2\sigma\sim\mu\}$ because then $$P_\mu=\{(\int d\sigma(t),\int td\sigma(t)) \mid \sigma\inM\mu\}$$.It is easy to see that$$M_\mu=\{t^{-2}d\nu(t)+a\delta_0\mid a\geq 0, \nu\sim\mu,\int
t^{-2}d\nu(t)<\infty\}$$. For an interior point $(x,y)$ of the parabolic region there are infinitely many measures $\sigma\in M\mu$ for which $$(x,y)=(\int d\sigma(t),\int td\sigma(t))$$. For a boundary point $(x,y)$ of the parabolic region there is exactly one measure $\sigma\in M_\mu$ with this property and it is given as $$\sigma=t^{-2}d\nu_c(t)$$, where $c$ is a special parameter value and $\nu_s$ is the family of Nevanlinna extremal measures in $V_\mu$, where the parameter $s$ ranges over the one-compactification of the real line. The special parameter value $c$ is the unique number for which $c=-1/y$. In other words, the boundary curve of the parabolic region has the parametric representation $$(\int t^{-2}d\nu_{-1/s}(t),s)$$, where $s$ runs over the real line. The unique measure $\sigma$ given above is a determinate measure, and the measures arising in this way from the boundary of parabolic regions associated with indeterminate measures $\mu$ can be described within the class of determinate measures using the index of determinacy introduced and used in recent manuscripts of Duran and myself, namely as the measures $\sigma$ for which $\ind_0(\sigma)=0$. All the results above except the last one with the index is in unpublished notes of mine from 1980 when I read the paper by Wright. If you think it is of interest I could perhaps publish it together with the index result. The last statement on Arimotos email: "Our conjecture is thatN-extremal measures are always found is such way" seems a little mysterious to me since the measures are determinate (and of index 0 at 0). However I realize that Akhiezer uses the word N-extremal in a double sense: Either a determinate measure or an indeterminate measure for which the polynomials are dense in $L^2$. (In the first case polynomials are also dense in $L^2$ by the Riesz theorem). I usually prefer to reserve the word N-extremal for the indeterminate case. In any case I thank Arimoto for having aroused my interest again in backwards extensions of Hamburger sequences and the parabolic regions. I look forward to hearing your comments. Sincerely yours Christian Berg |----------------------------------------------------------------------| | Christian Berg | | | Matematisk Institut | e-mail: berg@math.ku.dk | | Universitetsparken 5 | phone: +45 35320728 | | DK-2100 Copenhagen | fax: +45 35320704 | | Denmark | secretary: +45 35320722 | |----------------------------------------------------------------------| |----------------------------------------------------------------------| | Christian Berg | | | Matematisk Institut | e-mail: berg@math.ku.dk | | Universitetsparken 5 | phone: +45 35320728 | | DK-2100 Copenhagen | fax: +45 35320704 | | Denmark | secretary: +45 35320722 | |----------------------------------------------------------------------| Date: Mon, 13 Feb 1995 17:15:39 +0100 From: Christian Berg >Message-Id: <199502131615.AA17665@gelfand>To: a80919@tansei.cc.u-tokyo.ac.jpSubject: moment sequences X-Charset: ASCIIX-Char-Esc: 29Status: RODear Akio Arimoto,Some time ago I sent you an email concerning backward extensions ofmoment sequences. This was a reply to a question which reached me viaPaul Nevai and VanAssche. I wonder whether you have received my emailand if so I should like to hear your opinion. There was something inyour problem that was not so clear to me. Sincerely yours ChristianBergRemark: Professor Christian Berg is a very famous mathematician. I am very proud of his acquaintance. Viva internet!
Dear Christian Berg, Sorry I'm late in answering your e-mail. I received it on Jan 18th.I am grateful for your good comments to my question. If we take a point (s_{-2},s_{-1}) on the parabola P_{\mu}, we get thebackward extension which uniquely determines the measure \mu. This measureis N-extremal. My points were: (1) there is one to one correspondence between such \mu's and N-extreme measures derived from an indeterminate moment sequence (s_{0},s_{1},...). (2)The parabola is the limit case of the Parseval relation which is equivalent to the N-extreme property. Now I expect that m canonical measures will also appear from m-th backwardextensions. Can you explain the equation (3.6) in Wright's paper[1956]without using determinant's arguments? Sincerely yours, Akio Arimotooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo akio arimoto department of industrial engineering|o email:a80919@tansei.cc.u-tokyo.ac.jp musashi institute of technology |o telephone:(03) 3703-3111 setagaya-ku tamazutsumi 1-28-1 | o telefax: (03) 5707-2136 tokyo 158, japan |ooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo1.6I again posted to sci.math.research.Subject: Hamburger moment problem(3)Dear moderator\documentstyle{jarticle}\begin{document} Ch.Berg and J.P.R.Christensen ( Ann.Inst.Fourier 31(1981),p.107)have stated that if the measure $\mu$ arising from a Hamburger moment problemis indeterminate, then for N-extremal $\mu$,$$ h(x_n,x_m)=0,n\not=m,$$where $h(x,y)$ is the reproducing kernel associated with $\mu$ and $x_n$are the supporting points of $\mu$. When $\mu$ has the form $$\mu=\sum_{n=1}^{\infty}a_n\varepsilon_{x_n},a_n>0,$$ we easily see that for any $z$$$ inf_{p\in polynomials}\int \vert \frac{1}{x-z}-p\vert^2d\mu(x)$$$$ =\sum_{n=1}^{\infty}\vert\frac{1}{x_n-z}-\sum_{m=1}^{\infty}\frac{a_m}{x_m-z}h(x_n,x_m)\vert^2a_n.$$From this formula, we can see that $\mu$ is N-extremal iff$$h(x_n,x_m)=\delta _{n,m}/a_n.$$Is this well known? \end{document}oooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo akio arimoto department of industrial engineering|o email:a80919@tansei.cc.u-tokyo.ac.jp musashi institute of technology |o telephone:(03) 3703-3111 setagaya-ku tamazutsumi 1-28-1 | o telefax: (03) 5707-2136 tokyo 158, japan |ooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo1.7I asked a question to Prof.Berg by e-mail at 4/3/95.Dear Professor Berg,I have a question. In p.171 of the book [N.I.Akiezer, The classical moment problem], hehas stated Corollary 2 which can be rewritten compactly as: "The necessary and sufficient condition for an N-extremal measure tobelong to the moment sequence ${s_k}$ is that the set of all zeros {$\lambda_j$}of some entire function $q(z)$ and positive numbers $\mu_j$ satisfy$$[4.31]: \sum_1^{\infty}\frac{1}{\mu_j(1+\lambda_j^2)[q'(\lambda_j)]^2}<\infty$$ $$[4.34]: \sum_1^{\infty}\frac{1}{\mu_j[q'(\lambda_j)]^2}=\infty$$and$$[4.32]: s_m=\sum_1^{\infty}\mu_j\lambda_j^m.$$"For necessity these condition O.K. But for sufficiency I cannot follow hisideas. Especially I can't understand his statement in line 16,p.171 that ... self-adjoint and therefore the set of all polynomials is dense in $L_{\sigma}^2$. I think there is a situation such that in $L_{\sigma}^2$ the codimension of the set of all polynomials is positive. The condition [4.31] guarantees us the indeterminancy of the measure. However I can't show whether the condition [4.34] implies the denseness of the polynomials in $L_{\sigma}^2$ or not. Do I miss something? I should be grateful for any conmments on this question. Regards, Akio Arimotooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo akio arimoto department of industrial engineering|o email:a80919@tansei.cc.u-tokyo.ac.jp musashi institute of technology |o telephone:(03) 3703-3111 setagaya-ku tamazutsumi 1-28-1 | o telefax: (03) 5707-2136 tokyo 158, japan |ooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo
Professor Berg kindly replied me:
>N 1 berg@math.ku.dk Mon Apr 3 17:56 32/1692 "question"Message 1:From berg@math.ku.dk Mon Apr 3 17:56:07 1995Received: by gelfand id AA02688Date: Mon, 3 Apr 1995 10:55:27 +0200From: Christian Berg Message-Id: <199504030855.AA02688@gelfand>To: a80919@tansei.cc.u-tokyo.ac.jpDear Akio Akimoto, Thank you for the email with the question aboutAkhiezer. Some years ago I was puzzled by the same question and mystudent Henrik Pedersen and I tried to read Hamburgers original paperfrom Amer J. Math 1944. We realized that his proof as well asAkhiezers proof is wrong, but we could not settle if the theorem wastrue anyway. We were in correspondance with Paul Koosis from McGillwho finally constructed a counterexample, published in a note in C.R.Acad. Science Paris 311 (1990), 503-506. I shall send you themanuscript to my talk at the Stieltjes meeting in Delft in November1994, where I talked about the connection between entire functions andthe moment problem and it contains an outline of the result of Koosis.For your convieience I include an old letter I wrote to Krein in 1989about the mistake in Akhiezer. Unfortunately Krein had died a fewweeks before so I never got any answer.I regret that I have not yet found time to answer your question fromWrights paper. I shall return to that very soon. Sincerely yoursChristian BergFrom berg@math.ku.dk Tue Apr 4 21:14:06 1995 id AA10230; Tue, 4 Apr 95 21:13:55 JSTReceived: by gelfand id AA07555Date: Tue, 4 Apr 1995 14:13:28 +0200From: Christian Berg Message-Id: <199504041213.AA07555@gelfand>To: a80919@tansei.cc.u-tokyo.ac.jpSubject: Wrights paper X-Charset: ASCIIX-Char-Esc: 29Status: RDear Mr. Arimoto, I looked at Wrights equation 3.6. It is the Parsevalformula for the function $1/t^2$. If the measure \mu has a secondbackwards extension then $\int 1/t^4d\mu(t)<\infty$, and Parsevalsformula shows that the series is finite. I cannot see the converse inthe same easy way. Sincerely yours Christian Berg
I should be grateful for any
comments on this field. Thanks in advance.